Converting a PE Chain or Chains to a Ring
- Make all necessary physical connections between two edge PEs or between an edge PE and the CB. At least one end of the link must be one of these port types:
- (Optional, recommended) Connect multiple links between two units. The system will generate an SPX LAG connection on both units that includes all the links.
-
All ICX7750 samples need to be replaced with new samples based on an ICX 7650 stack.Initiate the conversion in one of these ways:
- In EXEC mode, enter the
spx interactive-setupcommand, and select either option 2 or 3 when prompted.ICX7750-26Q Router# spx interactive-setup You can abort spx interactive-setup at any stage by <ctrl-c> CBPE17PE18PE20PE21PE24data portPE21PE241G10Ga) T-connectionb) CB data portsd) different speedsPE21PE24c) PE data ports have configurationconfig 0: quit 1: change PE IDs 2: discover and convert new units (no startup-config flash) to PEs 3: discover and convert existing/new standalone units to PEs 2&3 can also find new links and convert chain(s) to ring. Please type your selection: 2 Probing topology to find new units...
- Enable zero-touch provisioning.
ICX7750-26Q Router(config)# spx cb-config ICX7750-26Q Router(config-spx-cb)# zero-touch-enable
New links are detected. Any invalid connection is reported in a system message, and you are asked to remove it. Valid connections and ring formation are reported in system output.The following example shows a warning message received after an invalid connection was detected.
Warning! The following 1 logical link(s) are invalid. Please remove them because they may cause loops. CB--PE17: error: CB 1/1/5 isn't spx-port/lag or ZTP-ports, 2 link(s): 1/1/5-17/3/1 1/1/7-17/4/1 Spx interactive-setup does not find any new unit spx interactive-setup detects invalid topology, aborts
The following example shows a system message received when a valid connection is detected that cannot be handled by the system. In this case, you are requested to use the
multi-spx-portormulti-spx-lagcommand to add the link, or to remove the link to avoid loops.The following 1 logical link(s) would expand existing spx-port/lag. They are not handled. Please manually use "multi-spx-port/lag" to add the link to existing spx-port/lag, or remove them because they may cause loops. PE17--PE27: 1 link(s): 17/2/1-27/2/1
- In EXEC mode, enter the
- After the process completes, enter the
write memorycommand to save the newly generated SPX port and SPX LAG configuration.
The following example shows SPX interactive-setup discovery of new links and conversion of two PE chains to a PE ring. Zero-touch provisioning works the same way but does not ask for user confirmation.
ICX7750-26Q Router# spx interactive-setup
You can abort spx interactive-setup at any stage by <ctrl-c>
CBPE17PE18PE20PE21PE24data portPE21PE241G10Ga) T-connectionb) CB data portsd) different speedsPE21PE24c) PE data ports have configurationconfig
0: quit
1: change PE IDs
2: discover and convert new units (no startup-config flash) to PEs
3: discover and convert existing/new standalone units to PEs
2&3 can also find new links and convert chain(s) to ring.
Please type your selection: 2
Probing topology to find new units...
Detect 2 new links (classified to 1 logical link) between existing units.
New logical link 0: =======================================================
+----+ +----+ +----+ +----+
2/1/9--4/1| 23 |2/1==2/1| 24 |2/5==2/1| 25 |2/5==2/5| 26 |
+----+ +----+ +----+ +----+
+----+ +----+
1/1/5==3/1| 17 |2/1==2/1| 27 |
+----+ +----+
The new logical link (PE26--PE27: 2 link(s): 26/2/1-27/2/3 26/2/2-27/2/4) will make the above two chains to form a ring.
Do you want to select this link? (enter 'y' or 'n'): y
spx interactive-setup discovers 1 link (valid#= 1, selected#= 1) and 0 chain
ICX7750-26Q Router#T=53m40.8: Add spx-lag 26/2/1 to 26/2/2 for PE 26 to form a ring. Please do "write memory".
T=53m40.8: Add spx-lag 27/2/3 to 27/2/4 for for PE 27 to form a ring. Please do "write memory".
ICX7750-26Q Router# write memory
ICX7750-26Q Router# show spx
… snipped
active standby
+---+ +---+ +---+
=2/1| 2 |2/4--2/4| 3 |2/1==2/1| 1 |2/4=
| +---+ +---+ +---+ |
| |
|-------------------------------------|
+----+ +----+ +----+ +----+ +----+
1/1/5==3/1| 17 |2/1==2/1| 27 |2/3==2/1| 26 |2/5==2/5| 25 |2/1==2/5| 24 |2/1=
+----+ +----+ +----+ +----+ +----+ |
|
+----+ |
2/1/9--4/1| 23 |2/1=
+----+